bantu jawab soal no 4 d dan e

semoga membantu yaa :)

d•
∫(x - 1)/x³ dx [2...1]
= ∫(x^-2 - x^-3) dx
= -1/x + 1/(2x^2)
= (-1/2 + 1) + (1/(2.2^2) - 1/2))
= 1/2 + (-3/8)
= 1/8

e•
∫(x - 1)/x√x dx [16...4]
= ∫(x^-1/2 - x^-3/2) dx
= 2√x + 2/√x
= (2√16 - 2√4) + (2/√16 - 2/√4)
= 4 - 1/2
= 7/2
= 3,5