Suatu barisan aritmatika diketahui U8 = 52 dan bedanya = 8 . Tentukan U14?. Tolong yah kak plisss!

Materi : Barisan dan Deret
kelas : IX SMP

U8 = U1 + 7b
52 = U1 + 7(8)
52 = U1 + 56
U1 = 52 - 56
U1 = -4

U14 = U1 + 13b
U14 = -4 + 13(8)
U14 = -4 + 104
U14 = 100

U8 = 52
b = 8
a = U8 - (n-1).b
= 52 - (8-1).8
= 52 - (7).8
= 52 - 56
*a = -4

*U14 = -4 + (13).8
= -4 + 104
= 100