pliss bantu jawab ya temen2 pelajaran matematika tentang turunan limit no 2 b-h

Turunan Fungsi Aljabar"

y = a xⁿ  → y' = an (x)ⁿ⁻¹

b)
y =  2x - 3/x
y = 2x - 3x⁻¹
y' = 2 + 3 x⁻²
y' = 2 + 3/x²

c)
y = 5x³ - 3
y' = 15x²

d)
y = 1 - 2x
y' = - 2

e)
y = (1 - 3x)²
y' = 2(1 -3x)(-3)
y' = -6(1 - 3x)
y' = 18x - 6

f)
y = ¹/₄ x⁻⁴
y' = -4(¹/₄) x⁻⁴⁻¹
y' = - x⁻⁵
y' = - 1/x⁵

g)
y = 6x⁻¹/²
y' = 6(-1/2) x⁻¹/²⁻¹
y' = - 3 x⁻³/²

h)
y = 3 x³/⁴
y' = 3/4(3) x³/⁴⁻¹
y' = 9/4 x⁻¹/⁴